Write a C program to calculate the following Sum:Sum=1-x2/2! +x4/4!-x6/6!+x8/8!-x10/10! - Code

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Thursday, October 6, 2011

Write a C program to calculate the following Sum:Sum=1-x2/2! +x4/4!-x6/6!+x8/8!-x10/10!


/* Write a C program to calculate the following Sum:
Sum=1-x2/2! +x4/4!-x6/6!+x8/8!-x10/10!
*/


#include <stdio.h>
#include <math.h>


void main()
{
int counter,f_coun;
float sum=0,x,power,fact;
clrscr();


printf("<-----------------------PROGRAM FOR SUM OF EQ. SERIES----------------------->");
printf("\n\n\tEQUATION SERIES : 1- X^2/2! + X^4/4! - X^6/6! + X^8/8! - X^10/10!");


printf("\n\n\n\tENTER VALUE OF X : ");
scanf("%f",&x);


for(counter=0, power=0; power<=10; counter++,power=power+2)
{
fact=1;
//CALC FACTORIAL OF POWER VALUE
for(f_coun=power; f_coun>=1; f_coun--)
        fact *= f_coun;
//EQ. FOR SUM SERIES
sum=sum+(pow(-1,counter)*(pow(x,power)/fact));
}


printf("SUM : %f",sum);
getch();


}

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