BRIDGE RECTIFER Electronic devices and circuits lab manual - Computer Programming

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## Wednesday, October 5, 2011

BRIDGE RECTIFER

AIM: - To calculate the ripple factor of a bridge rectifier, with and without filters.

APPARATUS:-
Experimental board
Diodes, IN4007 ---- 4 Nos.
Resistor, 1KΩ
Capacitor, 100μF/25v.
Transformer (6-0-6v)
Multi meters –2 No
Connecting Wires

CIRCUIT DIAGRAM:-

THEORY:-
The bridge rectifier is also a full-wave rectifier in which four p-n diodes are connected in the form of a bridge fashion. The Bridge rectifier has high efficiency when compared to half-wave rectifier. During every half cycle of the input, only two diodes will be conducting while other two diodes are in reverse bias.

PROCEDURE:-
1. Connections are made as per the circuit diagram.
2. Connect the ac main to the primary side of the transformer and secondary side to the bridge rectifier.
3. Measure the ac voltage at the input of the rectifier using the multi meter.
4. Measure both the ac and dc voltages at the output of the Bridge rectifier.
5. Find the theoretical value of dc voltage by using the formula,

CALCULATIONS:-
Theoretical calculations:-
Vrms = Vm/ √2
Vm =Vrms√2
Vdc=2Vm/П
(i)Without filter:
Ripple factor, r = √ ( Vrms/ Vdc )2 -1 = 0.482
(ii)With filter:

Ripple factor, r = 1/ (4√3 f C RL)         where    f =50Hz
C =100µF
RL=1KΩ
Practical Calculations:-
Without filter:-
Vac=
Vdc=
Ripple factor, r=Vac/Vdc
With filters:-
Vac=
Vdc=
Ripple factor,r=Vac/Vdc
OBSEVATIONS:-
Without Filter

 USING DMM Vac(v) Vdc(v) r= Vac/ Vdc

With Filter

 USING DMM Vac(v) Vdc(v) r= Vac/ Vdc

Without Filter:-
Vrms = Vm/ √2     ,   Vdc=2Vm/П ,   Vac=√( Vrms2- Vdc 2)

 USING CRO Vm(v) Vac(v) Vdc(v) r= Vac/ Vdc

WITHFILTER
 USINGCRO V1(V) V2(V) Vdc= (V1+V2)/2 Vac=(V1- V2)/2√3 r= Vac/ Vdc

MODELWAVEFORM:-

PRECAUTIONS:-

1. The voltage applied should not exceed in the ratings of the diode
2. The diodes will be connected correctly

RESULT:-

The Ripple factor of Bridge rectifier is with and without filter calculated.